8^(2)+9=((12)/(3)x2)-7

Solution for 8^(2)+9=((12)/(3)x2)-7 equation:

8^(2)+9=((12)/(3)x2)-7

We move all terms to the left:

8^(2)+9-(((12)/(3)x2)-7)=0


Domain of the equation: 3x2)-7)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-((+12/3x2)-7)+9+8^2=0

We add all the numbers together, and all the variables

-((+12/3x2)-7)+73=0

We multiply all the terms by the denominator


-((+12+73*3x2)-7)=0


We calculate terms in parentheses: -((+12+73*3x2)-7), so:

(+12+73*3x2)-7

We add all the numbers together, and all the variables

(73*3x2+12)-7

We get rid of parentheses

73*3x2+12-7

We add all the numbers together, and all the variables

73*3x2+5

Wy multiply elements

219x^2+5

Back to the equation:

-(219x^2+5)


We get rid of parentheses

-219x^2-5=0

a = -219; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-219)·(-5)
Δ = -4380
Delta is less than zero, so there is no solution for the equation